Nokea
A 16-year-old gravida 1 para 0 client has just been admitted to the hospital with a diagnosis of eclampsia. She's not presently convulsing. Which intervention should the nurse plan to include in this client's nursing care plan?
- A. Allow liberal family visitation
- B. Keep an airway at the bedside
- C. Assess temperature every hour
- D. Monitor blood pressure, pulse, and respiration every 4 hours
Correct Answer: B
Rationale: Keeping an airway at the bedside is crucial for a client with eclampsia, as there is a high risk of seizures that can obstruct the airway. Allowing liberal family visitation (choice A) may not be a priority at this time and can be overwhelming for the client. Assessing temperature every hour (choice C) is not directly related to managing eclampsia. Monitoring blood pressure, pulse, and respiration every 4 hours (choice D) is important but not as immediate as ensuring airway patency.
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_________ is self-propulsion.
- A. Mitosis
- B. Meiosis
- C. Motility
- D. Mutation
Correct Answer: C
Rationale: The correct answer is 'Motility.' Motility refers to the ability of cells or organisms to move by themselves, often through the use of specialized structures like flagella or cilia. Mitosis (Choice A) and Meiosis (Choice B) are processes related to cell division and genetic recombination, respectively, not self-propulsion. Mutation (Choice D) refers to changes in the DNA sequence and is not related to self-propulsion.
When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.
- A. monozygous
- B. dizygous
- C. homozygous
- D. hemizygous
Correct Answer: C
Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.
During a prenatal visit, for which of the following clients should the nurse auscultate the fetal heart rate?
- A. A client who has an ultrasound confirming a molar pregnancy
- B. A client who has a crown-rump length corresponding to 7 weeks gestation
- C. A client who has a positive urine pregnancy test 1 week after missed menses
- D. A client who has felt quickening for the first time
Correct Answer: D
Rationale: The correct answer is D because feeling quickening typically occurs around 18-20 weeks of gestation, indicating fetal movement. This is an appropriate time to auscultate the fetal heart rate. Choice A is incorrect because a molar pregnancy is not a viable pregnancy, and auscultating the fetal heart rate in this case is not applicable. Choice B is incorrect because a crown-rump length of 7 weeks gestation is too early for fetal heart rate auscultation. Choice C is incorrect because a positive urine pregnancy test alone does not indicate the appropriate timing for fetal heart rate auscultation.
A woman gave birth to a 7-pound, 6-ounce infant girl 1 hour ago. The birth was vaginal and the estimated blood loss (EBL) was 1500 ml. When evaluating the woman's vital signs, which finding would be of greatest concern to the nurse?
- A. Temperature 37.9°C, heart rate 120 beats per minute (bpm), respirations 20 breaths per minute, and blood pressure 90/50 mm Hg.
- B. Temperature 37.4°C, heart rate 88 bpm, respirations 36 breaths per minute, and blood pressure 126/68 mm Hg.
- C. Temperature 38°C, heart rate 80 bpm, respirations 16 breaths per minute, and blood pressure 110/80 mm Hg.
- D. Temperature 36.8°C, heart rate 60 bpm, respirations 18 breaths per minute, and blood pressure 140/90 mm Hg.
Correct Answer: A
Rationale: An estimated blood loss (EBL) of 1500 ml following a vaginal birth is significant and can lead to hypovolemia. The vital signs provided in option A (Temperature 37.9°C, heart rate 120 bpm, respirations 20 breaths per minute, and blood pressure 90/50 mm Hg) indicate tachycardia and hypotension, which are concerning signs of hypovolemia due to excessive blood loss. Tachycardia is the body's compensatory mechanism to maintain cardiac output in response to decreased blood volume, and hypotension indicates inadequate perfusion. Options B, C, and D do not exhibit the same level of concern for hypovolemia. Option B shows tachypnea, which can be a result of pain or anxiety postpartum. Option C and D have vital signs within normal limits, which are not indicative of the body's response to significant blood loss.
What is the typical sex chromosome pattern for females?
- A. XX
- B. XYY
- C. XY
- D. XXY
Correct Answer: A
Rationale: The typical sex chromosome pattern for females is XX. Females have two X chromosomes, which is represented as XX. Choice B (XYY) is incorrect as it represents the sex chromosome pattern for males with an extra Y chromosome. Choice C (XY) is the sex chromosome pattern for males. Choice D (XXY) represents a genetic disorder known as Klinefelter syndrome, where males have an extra X chromosome.