Nokea
A client is 4 hours postpartum and is experiencing hypovolemic shock. Which of the following actions should the nurse take?
- A. Administer indomethacin
- B. Insert a second 22-gauge IV catheter.
- C. Insert an indwelling urinary catheter.
- D. Administer oxygen at 4L/min via nasal cannula.
Correct Answer: D
Rationale: In hypovolemic shock, there is decreased oxygen delivery to tissues. Administering oxygen at 4L/min via nasal cannula can help improve oxygenation and support tissue perfusion. Indomethacin (Choice A) is a nonsteroidal anti-inflammatory drug and is not indicated in the management of hypovolemic shock. Inserting a second 22-gauge IV catheter (Choice B) may be necessary for fluid resuscitation, but oxygen administration takes precedence. Inserting an indwelling urinary catheter (Choice C) may be considered for monitoring urinary output, but it is not the priority action in managing hypovolemic shock.
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When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.
- A. monozygous
- B. dizygous
- C. homozygous
- D. hemizygous
Correct Answer: C
Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.
Daisy was always unusually short for her age. She was unable to conceive a child after marriage, and upon visiting a doctor, she was prescribed estrogen replacement therapy. Daisy is most likely suffering from:
- A. Phenylketonuria (PKU).
- B. Cystic fibrosis.
- C. Turner syndrome.
- D. Huntington's disease (HD).
Correct Answer: C
Rationale: Daisy's symptoms of short stature and infertility, along with the prescription of estrogen replacement therapy, are indicative of Turner syndrome. Turner syndrome is a genetic condition in which a female is partially or completely missing one X chromosome. This results in short stature, infertility, and other physical characteristics. Phenylketonuria (PKU) is a metabolic disorder caused by a mutation in the gene responsible for the breakdown of the amino acid phenylalanine. Cystic fibrosis is a genetic disorder affecting the respiratory and digestive systems. Huntington's disease (HD) is a neurodegenerative disorder that affects muscle coordination and leads to cognitive decline.
A primigravida is being monitored at the prenatal clinic for preeclampsia. Which finding is of greatest concern to the nurse?
- A. Blood pressure (BP) increased to 138/86 mm Hg.
- B. Weight gain of 0.5 kg during the past 2 weeks.
- C. Dipstick value of 3+ for protein in her urine.
- D. Pitting pedal edema at the end of the day.
Correct Answer: C
Rationale: The correct answer is C. Proteinuria, indicated by a dipstick value of 3+ in the urine, is a significant concern in a patient being monitored for preeclampsia. Proteinuria is a key diagnostic criterion for preeclampsia, and a value of 3+ signifies a substantial amount of protein in the urine, warranting further evaluation. While an increase in blood pressure to 138/86 mm Hg is slightly elevated, it does not meet the diagnostic threshold for severe hypertension in preeclampsia. A weight gain of 0.5 kg over 2 weeks is within normal limits and not as concerning as significant rapid weight gain. Pitting pedal edema, though common in pregnancy, is not a specific indicator of preeclampsia and is considered a less concerning finding compared to significant proteinuria.
In the prenatal record, the nurse should record for the pregnant client who has a 3-year-old child at home, a term birth, a miscarriage at 10 weeks' gestation, and a set of twins who died within 24 hours:
- A. Gravida 2, para 1.
- B. Gravida 3, para 3.
- C. Gravida 4, para 2.
- D. Gravida 5, para 4.
Correct Answer: C
Rationale: The correct answer is C: 'Gravida 4, para 2.' Gravida refers to the total number of pregnancies, including the current one. In this case, the client has been pregnant a total of 4 times, so gravida is 4. Para is the number of pregnancies that have reached viability, which is 2 in this case. The client has had a term birth and a set of twins who died within 24 hours, totaling 2 pregnancies that reached viability. Choices A, B, and D are incorrect because they do not accurately reflect the client's obstetric history based on the information provided.
A 17-year-old client gave birth 12 hours ago. She states that she doesn't know how to care for her baby. To promote parent-infant attachment behaviors, which intervention should the nurse implement?
- A. Ask if she has help to care for the baby at home
- B. Provide a video on newborn safety and care
- C. Explore the basis of fears with the client
- D. Encourage rooming in while in the hospital
Correct Answer: D
Rationale: Encouraging rooming in while in the hospital is the most appropriate intervention to promote parent-infant attachment behaviors. Rooming in allows the mother to stay with her baby continuously, facilitating bonding and providing the opportunity for the mother to learn how to care for her baby with the nurse's support. Asking if she has help at home (Choice A) does not directly address promoting attachment behaviors. Providing a video on newborn safety and care (Choice B) may offer information but does not actively facilitate immediate bonding. Exploring the basis of fears (Choice C) is important but may not directly address promoting attachment behaviors as effectively as encouraging rooming in.