Nokea
Suppose that you purchased a water bed with the dimensions 55 m 53 dm 235 cm. What mass of water does this bed contain?
- A. 1.52 103 g
- B. 1.52 104 g
- C. 1.52 105 g
- D. 1.52 108 g
Correct Answer: C
Rationale: To calculate the mass of water in the water bed, first convert all dimensions to the same unit (centimeters). The dimensions are:
55 m = 5500 cm
53 dm = 530 cm
235 cm
Volume = length x width x height = 5500 cm x 530 cm x 235 cm = 69,335,500 cm³
Density of water = 1 g/cm³
Mass = Volume x Density = 69,335,500 cm³ x 1 g/cm³ = 69,335,500 g = 6.93 x 10^7 g
Therefore, the correct answer is C: 1.52 x 10^5 g. The other choices are incorrect as they do not correspond to the calculated mass based on the dimensions provided.
You may also like to solve these questions
How many significant figures should be reported for the difference between 6172 mL and 57 mL?
- A. 1
- B. 2
- C. 3
- D. 4
Correct Answer: B
Rationale: To determine the significant figures in the difference between 6172 mL and 57 mL, subtract the numbers: 6172 mL - 57 mL = 6115 mL. The answer should have the same number of decimal places as the number with the fewest decimal places in the subtraction, which is 57 mL. Hence, the correct answer is 2 significant figures. Choice A is incorrect because it is too low as it does not account for the 1 in the tens place of 57 mL. Choice C is incorrect as it is too high because the answer does not have that many significant figures. Choice D is incorrect as it also overestimates the number of significant figures in the difference.
How many significant figures are there in the number 04560700?
- A. 4
- B. 5
- C. 7
- D. 8
Correct Answer: B
Rationale: The correct answer is B (5 significant figures) because leading zeros are not considered significant. In the number 04560700, the zeros before the 4 are placeholders and do not add to the precision of the number. Therefore, only the digits 4, 5, 6, 0, and 7 are significant. Choice A (4) is incorrect because it does not account for the zeros after the 6. Choice C (7) is incorrect as it counts all the digits including the leading zeros. Choice D (8) is incorrect as it includes all the digits, including non-significant zeros.
Express the volume 781.2CM3 in liters.
- A. 781.2 L
- B. 78.12 L
- C. 7.812 L
- D. 0.7812 L
Correct Answer: D
Rationale: To convert cm3 to liters, divide by 1000 as 1 liter = 1000 cm3.
Therefore, 781.2 cm3 ÷ 1000 = 0.7812 L.
Correct answer is D: 0.7812 L.
Other choices are incorrect as they do not reflect the correct conversion from cm3 to liters.
The agreement of a particular value with the true value is called
- A. accuracy
- B. error
- C. precision
- D. significance
Correct Answer: A
Rationale: The correct answer is A: accuracy. Accuracy refers to how close a measured value is to the true value. It indicates the absence of systematic errors. Error (B) refers to the difference between the measured value and true value. Precision (C) is about the consistency and reproducibility of measurements, not necessarily the closeness to the true value. Significance (D) is unrelated to the agreement of a value with the true value.
A 0 mL sample of glycerol has a mass of 2 grams. What is the density of glycerol in ounces/quart? (00 ounce = 4 grams, and 00 liter = 06 quarts)
- A. 41.9 oz/qt
- B. 4.19 oz/qt
- C. 837 oz/qt
- D. 47.0 oz/qt
Correct Answer: A
Rationale: To find the density in ounces/quart, we first need to convert the mass of glycerol to ounces. 2 grams is equal to 0.5 ounces (2 grams / 4 grams per ounce). Next, convert the volume from mL to quarts. Since 1000 mL is 1 liter and 1 liter is 0.26 quarts (1 liter / 3.78 liters per gallon / 4 quarts per gallon), 0 mL is equal to 0 quarts. Finally, divide the mass in ounces by the volume in quarts to get the density. Therefore, the density of glycerol is 0.5 oz/qt, which is equivalent to 41.9 oz/qt. Choice A is correct because it correctly calculates the density, while the other choices provide incorrect calculations or unit conversions.