Nokea
A client with chronic kidney disease is advised to follow a low-phosphorus diet. Which food should the client avoid?
- A. Milk
- B. Apples
- C. Carrots
- D. Rice
Correct Answer: A
Rationale: Correct Answer: Milk. Milk is high in phosphorus and should be avoided in a low-phosphorus diet for clients with chronic kidney disease. Choice B (Apples), C (Carrots), and D (Rice) are not significant sources of phosphorus and can be included in moderation in a low-phosphorus diet. Apples and carrots are generally considered healthy choices for most individuals, while rice is a staple food that is low in phosphorus and can be part of a renal diet.
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The client with osteoporosis is being taught about dietary modifications by the nurse. Which food should the nurse recommend to increase calcium intake?
- A. Broccoli
- B. Chicken breast
- C. White bread
- D. Apple
Correct Answer: A
Rationale: Broccoli is the correct answer as it is a good source of calcium, which is essential for clients with osteoporosis. Broccoli is a green leafy vegetable that provides a significant amount of calcium. Chicken breast, white bread, and apple do not contain as much calcium as broccoli and therefore are not the best choices to recommend for increasing calcium intake in clients with osteoporosis.
A client with rheumatoid arthritis has elevated serum rheumatoid factor. Which interpretation of this finding should the nurse make?
- A. Evidence of spread of the disease to the kidney.
- B. Confirmation of the autoimmune disease process.
- C. Representative of a decline in the client's condition.
- D. Indication of the onset of joint degeneration.
Correct Answer: B
Rationale: The correct interpretation of elevated serum rheumatoid factor in a client with rheumatoid arthritis is confirmation of the autoimmune disease process. Rheumatoid factor is a marker for autoimmune activity, thus confirming the diagnosis of rheumatoid arthritis. Choice A is incorrect as elevated rheumatoid factor does not specifically indicate spread of the disease to the kidney. Choice C is incorrect as elevated rheumatoid factor does not always represent a decline in the client's condition. Choice D is incorrect as elevated rheumatoid factor is not an indication of the onset of joint degeneration, but rather points towards autoimmune activity.
A client with cancer is receiving chemotherapy with a known vesicant. The client's IV has been in place for 72 hours. The nurse determines that a new IV site cannot be obtained and leaves the present IV in place. What is the greatest clinical risk related to this situation?
- A. Impaired skin integrity
- B. Fluid volume excess
- C. Acute pain and anxiety
- D. Peripheral neurovascular dysfunction
Correct Answer: A
Rationale: The correct answer is A: Impaired skin integrity. In this situation, the greatest clinical risk is related to impaired skin integrity due to the potential extravasation of the vesicant. Vesicants are substances that can cause severe tissue damage if they leak into the surrounding tissues. Choices B, C, and D are not the most significant risks in this scenario. Fluid volume excess, acute pain, and peripheral neurovascular dysfunction are not directly associated with leaving the IV in place with a known vesicant for an extended period.
When conducting a class for parents about sudden infant death syndrome (SIDS), the nurse instructs the class that the infant should be placed in which position to sleep?
- A. Right side-lying
- B. Left side-lying
- C. Prone
- D. Supine
Correct Answer: D
Rationale: The correct answer is D, supine. The American Academy of Pediatrics recommends placing infants on their back, or supine, to sleep as it has been shown to reduce the risk of SIDS. Choices A, B, and C are incorrect because placing infants on their right side, left side, or prone (on their stomach) respectively are not recommended sleeping positions due to the increased risk of SIDS associated with those positions.
A client with hyperthyroidism is prescribed methimazole. Which adverse effect should the nurse monitor for?
- A. Agranulocytosis
- B. Hypoglycemia
- C. Bradycardia
- D. Hypercalcemia
Correct Answer: A
Rationale: The correct answer is Agranulocytosis. Methimazole, used to treat hyperthyroidism, can lead to agranulocytosis, a severe decrease in white blood cells. This condition increases the risk of infections and requires immediate medical attention. Hypoglycemia (choice B) is not a common adverse effect of methimazole. Bradycardia (choice C) is unlikely as methimazole tends to have minimal effects on heart rate. Hypercalcemia (choice D) is not associated with methimazole use.