Nokea
A worker in a warehouse ships 9 boxes each day. If every box must contain 3 shipping labels, how many shipping labels does the worker need each day?
- A. 24 labels
- B. 27 labels
- C. 20 labels
- D. 30 labels
Correct Answer: B
Rationale: To find the total number of shipping labels needed, multiply the number of boxes by the labels per box: 9 boxes * 3 labels per box = 27 labels. Therefore, the worker needs 27 shipping labels each day. Choice A, 24 labels, is incorrect because it results from multiplying 9 boxes by 3 labels without calculating the correct total. Choice C, 20 labels, is incorrect as it underestimates the total number of labels needed. Choice D, 30 labels, is incorrect as it overestimates the total by multiplying incorrectly.
You may also like to solve these questions
Subtract 5/6 - 3/4.
- A. 1/12
- B. 2/24
- C. 1/2
- D. 1/8
Correct Answer: A
Rationale: To subtract fractions, find a common denominator. The common denominator for 6 and 4 is 12. So, 5/6 = 10/12 and 3/4 = 9/12. Subtracting 10/12 - 9/12 gives us 1/12 as the result. Choice A, 1/12, is the correct answer because it represents the simplified result of subtracting the fractions with the common denominator. Choices B, C, and D are incorrect because they do not reflect the correct subtraction result of 1/12 after finding the common denominator.
What is the probability of rolling an odd number on a six-sided die?
- A. 50%
- B. 66.70%
- C. 33.30%
- D. 25%
Correct Answer: A
Rationale: A six-sided die has three odd numbers (1, 3, 5) out of six possible outcomes. To calculate the probability, divide the number of favorable outcomes (odd numbers) by the total number of outcomes: 3/6 = 0.5 or 50%. Therefore, the probability of rolling an odd number on a six-sided die is 50%. Choice A is correct. Choice B (66.70%) is incorrect as it does not represent the correct probability of rolling an odd number on a six-sided die. Choice C (33.30%) is incorrect as it represents the probability of rolling an even number. Choice D (25%) is incorrect as it does not reflect the correct probability of rolling an odd number on a six-sided die.
If a person can type 45 words per minute, how many words can they type in 20 minutes?
- A. 800 words
- B. 850 words
- C. 900 words
- D. 750 words
Correct Answer: C
Rationale: To find out how many words a person can type in 20 minutes at a speed of 45 words per minute, you multiply the typing speed (45 words/minute) by the duration (20 minutes): 45 words/minute x 20 minutes = 900 words. Hence, the correct answer is 900 words. Choice A (800 words) is incorrect because it results from multiplying 45 words per minute by 18 minutes, not 20. Choice B (850 words) is incorrect as it is not the product of 45 words per minute and 20 minutes. Choice D (750 words) is incorrect because it is the outcome of multiplying 45 words per minute by 15 minutes, not 20.
If a marathon runner burns 2276 calories in 21.4 miles, what is their rate of calories burned per mile?
- A. 107.5
- B. 106.4
- C. 105.6
- D. 109.3
Correct Answer: B
Rationale: To find the rate of calories burned per mile, divide the total calories burned by the total miles run: 2276 · 21.4 ≈ 106.4 calories per mile. This calculation gives the average number of calories burned for each mile of the marathon. Choice A, 107.5, is incorrect as it does not match the precise calculation result. Choices C and D are also incorrect as they are not the accurate rate of calories burned per mile based on the given data.
A decorative box has a rectangular base (20cm by 15cm) and a hemispherical top with the same diameter as the base. What is the total surface area of the box (excluding the base)?
- A. 825 sq cm
- B. 1075 sq cm
- C. 1325 sq cm
- D. 1575 sq cm
Correct Answer: C
Rationale: To find the total surface area of the box excluding the base, calculate the lateral surface area of the rectangular base and the surface area of the hemisphere. The lateral surface area of the rectangular base is 2(20cm x 15cm) = 600 sq cm. The surface area of the hemisphere is 2πr^2, where r is half the diameter of the base, so r = 10cm. Thus, the surface area of the hemisphere is 2π(10cm)^2 = 200π sq cm ≈ 628.32 sq cm. Add the lateral surface area of the base and the surface area of the hemisphere: 600 sq cm + 628.32 sq cm ≈ 1228.32 sq cm. Therefore, the total surface area of the box is approximately 1228.32 sq cm, which is closest to 1325 sq cm (Choice C). Choices A, B, and D are incorrect as they do not represent the accurate calculation of the total surface area of the box.