Complications of salpingitis include:
- A. Pyosalpinx
- B. Peritonitis
- C. Endometriosis
- D. Infertility
Correct Answer: A
Rationale: The correct answer is A: Pyosalpinx. Salpingitis is inflammation of the fallopian tubes, which can lead to the accumulation of pus within the tube, known as pyosalpinx. This is a common complication of salpingitis due to the infection causing the tubes to become blocked and filled with pus. Peritonitis (B) is inflammation of the peritoneum, not directly related to salpingitis. Endometriosis (C) is a separate condition where endometrial tissue grows outside the uterus. Infertility (D) can be a complication of salpingitis, but pyosalpinx is a more direct and immediate consequence.
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Which of the following reasons would make a client who was treated successfully for a chlamydia infection at a greater risk for acquiring AIDS?
- A. The tissue irritation may be permanent, despite successful eradication of the bacteria.
- B. The immune system is already compromised.
- C. The bacterium Chlamydia trachomatis causes AIDS.
- D. The bacterium Chlamydia trachomatis continues to live inside the cells it has infected.
Correct Answer: B
Rationale: Having had an STI indicates existing vulnerabilities in the immune system, increasing susceptibility to HIV/AIDS.
If a cell has 46 chromosomes at the beginning of mitosis, determine the number of chromatids at
- B. 23 chromatids
- C. 46 chromatids
- D. 92 chromatids
Correct Answer: D
Rationale: The correct answer is D: 92 chromatids. In mitosis, each chromosome consists of two sister chromatids. Since the cell begins with 46 chromosomes, there are a total of 92 chromatids present. This is because each chromosome duplicates during the S phase of interphase, resulting in two identical sister chromatids held together by a centromere. Therefore, the total number of chromatids in the cell at the beginning of mitosis is twice the number of chromosomes. Choices A, B, and C are incorrect because they do not account for the duplication of chromatids that occurs during the cell cycle.
A nurse is working with a client who has undergone chemotherapy for breast cancer. The client is experiencing body image disturbances. Which of the following symptoms would contribute to this psychosocial issue?
- A. Fatigue
- B. Vomiting
- C. Hair loss
- D. Nausea
Correct Answer: C
Rationale: Hair loss is a visible side effect of chemotherapy that can significantly impact body image.
A young woman is given daily injections of a substance beginning on the 16th day of her normal menstrual cycle and continuing for 3 weeks. As long as the injections continue, she does not menstruate. The injected substance could be which of the following?
- A. Testosterone
- B. FSH
- C. An inhibitor of progesterone’s actions
- D. A prostaglandin E2 inhibitor
Correct Answer: C
Rationale: The correct answer is C: An inhibitor of progesterone’s actions. Progesterone is responsible for maintaining the uterine lining, and inhibiting its actions would prevent menstruation. Testosterone (A) and FSH (B) do not directly affect menstruation. Prostaglandin E2 (D) is involved in the menstrual process, but inhibiting it would not necessarily stop menstruation.
The primary germ layer that gives rise
- A. areolar glands to the mucosae and associated glands
- B. lacrimal glands is the ________.
- C. sweat glands
- D. ectoderm
Correct Answer: D
Rationale: The correct answer is D: ectoderm. The primary germ layer that gives rise to structures like the lacrimal glands is the ectoderm, which is one of the three primary germ layers during embryonic development. The ectoderm gives rise to tissues such as the epidermis of the skin, nervous system, and various glands including lacrimal glands. Choice A, areolar glands to the mucosae and associated glands, is incorrect as they are derived from the mesoderm. Choice C, sweat glands, is also incorrect as they are derived from the ectoderm but are not the primary germ layer responsible for lacrimal glands. Choice B, lacrimal glands is the _______, is incorrect as it does not provide a complete statement and is not a primary germ layer.