Dengue is a common vector-borne disease prevalent in tropical countries. Which of the following statement is true for dengue fever?
- A. It is caused by a DNA virus
- B. The vector once infected with the virus remains infective for life
- C. The vector prefers polluted water for propagation
- D. Joint symptoms are commoner in dengue fever compared to chikungunya
Correct Answer: B
Rationale: The correct answer is B because the Aedes mosquito, the vector for dengue fever, remains infective for life once it is infected with the dengue virus. This is due to the virus establishing a lifelong infection in the mosquito's salivary glands. The other choices are incorrect because: A) Dengue is caused by an RNA virus, not a DNA virus. C) The Aedes mosquito prefers clean, stagnant water for breeding, not polluted water. D) Joint symptoms are commoner in chikungunya, not dengue fever.
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An 18-year old male patient presents with bruising, fatigue, and diffuse extremity pain. He is noted to be tachypneic and hypoxic and has a diffuse interstitial infiltrate on chest x-ray. CBC reveals a WBC count of 285,000/mm3 (85% myeloblasts, with monocytic morphology), hemoglobin of 7.9 g/dL, and platelet count of 36,000/mm3. What is the most likely cause of the infiltrate and respiratory symptoms and the most appropriate initial treatment?
- A. Hyperleukocytosis; initiation of induction chemotherapy
- B. Hyperleukocytosis; leukapheresis or manual exchange transfusion and initiation of induction chemotherapy
- C. COVID-19 infection; convalescent plasma and prednisone
- D. Pneumococcal pneumonia; vancomycin
Correct Answer: B
Rationale: The correct answer is B: Hyperleukocytosis; leukapheresis or manual exchange transfusion and initiation of induction chemotherapy. In this scenario, the patient's symptoms and lab findings are consistent with acute myeloid leukemia (AML) with leukostasis, causing hypoxia and interstitial infiltrates. Leukapheresis or manual exchange transfusion is crucial to rapidly reduce the high white blood cell count, which can help alleviate symptoms and prevent complications like tissue hypoxia. Initiation of induction chemotherapy is also essential for long-term management of AML.
Rationale for why other choices are incorrect:
A: Hyperleukocytosis alone without leukostasis does not typically require immediate leukoreduction, as in this case. Induction chemotherapy should be initiated promptly to address the underlying AML.
C: COVID-19 infection would not typically present with such profound leukocytosis and monocytic morphology. Convalescent plasma and prednisone are not
RBCs break into fragments, they are referred to as schistocytes. These type of cells are seen in
- A. Sickle cell trait
- B. Thalassemia
- C. Microangiopathic hemolytic anemia
- D. Idiopathic thrombocytopenic purpura
Correct Answer: C
Rationale: The correct answer is C: Microangiopathic hemolytic anemia. Schistocytes are fragmented red blood cells seen in conditions where RBCs are physically sheared or damaged as they pass through small blood vessels. In microangiopathic hemolytic anemia, abnormal or damaged blood vessels cause mechanical destruction of RBCs, leading to the formation of schistocytes. Sickle cell trait (A) and Thalassemia (B) are genetic disorders that do not typically cause schistocytes. Idiopathic thrombocytopenic purpura (D) is a condition characterized by low platelet count, not associated with schistocytes.
According to the FAB classification, the L2 stage is characterized by:
- A. Large heterogenous blasts with prominent nucleoli
- B. Small homogenous blasts with scanty nucleoli and higher nucleus to cytoplasm ratio
- C. Large homogenous blasts with scanty nucleoli and higher nucleus to cytoplasm ratio
- D. Large blasts with basophilic vacuolated cytoplasm
Correct Answer: C
Rationale: The correct answer is C because according to the FAB classification, the L2 stage is characterized by large homogenous blasts with scanty nucleoli and a higher nucleus to cytoplasm ratio. This is because in the L2 stage, the blasts are more immature and have a larger size compared to other stages. Choice A is incorrect because it describes blasts with prominent nucleoli, which is not characteristic of the L2 stage. Choice B is incorrect because it describes small homogenous blasts with scanty nucleoli, which does not align with the characteristics of the L2 stage. Choice D is incorrect because it describes large blasts with basophilic vacuolated cytoplasm, which is not a feature of the L2 stage.
The health care provider tells the nurse that a client is to be started on a platelet inhibitor. About what drug does the nurse plan to teach the client?
- A. Clopidogrel (Plavix)
- B. Enoxaparin (Lovenox)
- C. Reteplase (Retavase)
- D. Warfarin (Coumadin)
Correct Answer: A
Rationale: The correct answer is A: Clopidogrel (Plavix). Clopidogrel is a platelet inhibitor that helps prevent blood clots by inhibiting platelet aggregation. It is commonly used to reduce the risk of heart attack or stroke. Enoxaparin (Lovenox) is a low molecular weight heparin that works by preventing blood clots by inhibiting clotting factors. Reteplase (Retavase) is a thrombolytic agent used to dissolve blood clots in emergency situations. Warfarin (Coumadin) is an anticoagulant that works by inhibiting vitamin K-dependent clotting factors. Clopidogrel is the most appropriate choice for a platelet inhibitor in this scenario due to its mechanism of action and indication for preventing blood clots.
You are caring for a patient with a large localized Ewing sarcoma of the soft tissues of the arm. The surgeon believes that the tumor can be resected without amputation but asks whether you can give some chemotherapy to shrink the tumor before surgery. Which of the following would you tell the surgeon?
- A. If the tumor can be resected without amputation, then the best time to do the resection is before any chemotherapy to improve the prognosis.
- B. You agree with waiting to do the resection until week 12 of therapy and will begin chemotherapy; you recognize that radiotherapy will not be necessary if the tumor is completely resected at week 12 of therapy.
- C. You agree with waiting to do the resection until week 12 of therapy and will begin chemotherapy; you recognize that radiotherapy will be necessary even if the tumor is completely resected at week 12 of therapy.
- D. If the tumor can be resected without amputation, then the best time to do the resection is before any chemotherapy; you recognize that this is the only way to avoid radiotherapy.
Correct Answer: B
Rationale: Step 1: Agreeing to wait until week 12 of therapy before resection allows chemotherapy to shrink the tumor, making surgery easier and potentially less extensive.
Step 2: Waiting until week 12 also helps assess the tumor's response to chemotherapy, guiding further treatment decisions.
Step 3: Choosing not to delay the resection until week 12 may risk more extensive surgery or complications due to the tumor's size.
Step 4: Opting for radiotherapy regardless of tumor resection status at week 12 is not advisable as unnecessary radiation exposure should be avoided unless absolutely necessary.