Erma has her eye on two sweaters at her favorite clothing store, but she has been waiting for the store to offer a sale. This week, the store advertises 25% off a second item of equal or lesser value. One sweater is $50, and the other is $44. What will Erma spend?
- A. $79
- B. $81
- C. $83
- D. $85
Correct Answer: C
Rationale: Erma receives a 25% discount on the $44 sweater, which amounts to a $11 discount. Therefore, she pays $44 - $11 = $33 for this sweater. Adding this discounted price to the $50 sweater, Erma will spend a total of $50 + $33 = $83. Choice A, $79, is incorrect because it does not include the correct calculation for the discounted sweater. Choice B, $81, is incorrect as it does not consider the discounts on both sweaters. Choice D, $85, is incorrect since it overestimates the total amount Erma will spend.
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Solve for x: 3(x - 1) = 2(3x - 9)
- A. x = 2
- B. x = 8/3
- C. x = -5
- D. x = 5
Correct Answer: D
Rationale: To solve the equation 3(x - 1) = 2(3x - 9), first distribute and simplify both sides to get 3x - 3 = 6x - 18. Next, subtract 3x from both sides to get -3 = 3x - 18. Then, add 18 to both sides to obtain 15 = 3x. Finally, divide by 3 to find x = 5. Therefore, the correct answer is x = 5. Choices A, B, and C are incorrect because they do not represent the correct solution to the given equation after proper algebraic manipulation.
A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?
- A. 56
- B. 244
- C. 488
- D. 672
Correct Answer: C
Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.
Which of the following is listed in order from least to greatest? (-2, -3/4, -0.45, 3%, 0.36)
- A. -2, -3/4, -0.45, 3%, 0.36
- B. -3/4, -0.45, -2, 0.36, 3%
- C. -0.45, -2, -3/4, 3%, 0.36
- D. -2, -3/4, -0.45, 0.36, 3%
Correct Answer: A
Rationale: To determine the order from least to greatest, convert all the values to a common form. When written in decimal form, the order is -2, -0.75 (which is equal to -3/4), -0.45, 0.03 (which is equal to 3%), and 0.36. Therefore, the correct order is -2, -3/4, -0.45, 3%, 0.36 (Choice A). Choice B is incorrect as it has the incorrect placement of -2 and 0.36. Choice C is incorrect as it incorrectly places -0.45 before -2. Choice D is incorrect as it incorrectly places 0.36 before 3%.
A rectangular solid box has a square base with a side length of 5 feet and a height of h feet. If the volume of the box is 200 cubic feet, which of the following equations can be used to find h?
- A. 5h = 200
- B. 5h² = 200
- C. 25h = 200
- D. h = 200 · 5
Correct Answer: C
Rationale: The volume formula for a rectangular solid is V = l w h. In this case, the length and width are both 5 feet. Substituting the values into the formula gives V = 5 5 h = 25h = 200. Therefore, h = 200 · 25 = 8. Option A is incorrect because the product of length, width, and height is not directly equal to the volume. Option B is incorrect as squaring the height is not part of the volume formula. Option D is incorrect as it oversimplifies the relationship between height and volume, not considering the base dimensions.
Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?
- A. 128 pounds
- B. 150 pounds
- C. 175 pounds
- D. 180 pounds
Correct Answer: B
Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.