Nokea
How many centimeters are in 7 meters?
- A. 7 m = 7 cm
- B. 7 m = 70 cm
- C. 7 m = 700 cm
- D. 7 m = 7000 cm
Correct Answer: C
Rationale: The prefix 'centi-' means one-hundredth. In the metric system, 1 meter is equal to 100 centimeters. Therefore, to convert meters to centimeters, you multiply the number of meters by 100. In this case, 7 meters is equal to 7 * 100 = 700 centimeters. Choice A is incorrect as it does not consider the conversion factor properly. Choice B is incorrect as it only accounts for a factor of 10 instead of 100. Choice D is incorrect as it overestimates the conversion by a factor of 10.
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The first midwife uses 2/5 of her monthly contribution to pay for rent and utilities. She saves half of the remainder for incidental expenditures, and uses the rest of the money to purchase medical supplies. How much money does she spend on medical supplies each month?
- A. $600
- B. $800
- C. $1,000
- D. $1,200
Correct Answer: A
Rationale: The first midwife contributes $2000. She spends $800 on rent and utilities. After paying for rent and utilities, $1200 remains. Half of this amount, which is $600, is saved for incidental expenditures. Therefore, the first midwife spends the remaining $600 on purchasing medical supplies each month. Choice A, $600, is the correct answer. Choices B, C, and D are incorrect as they do not accurately reflect the amount spent on medical supplies as calculated in the given scenario.
A lab technician took 100 hairs from a patient to conduct several tests. The technician used 1/7 of the hairs for a drug test. How many hairs were used for the drug test? (Round your answer to the nearest hundredth.)
- A. 14
- B. 14.2
- C. 14.29
- D. 14.3
Correct Answer: C
Rationale: To find how many hairs were used for the drug test, you need to calculate 1/7 of 100. 1/7 of 100 is 14.2857, which rounds to 14.29 when rounded to the nearest hundredth. Therefore, 14.29 hairs were used for the drug test. Choice A is incorrect as it does not account for rounding to the nearest hundredth. Choices B and D are incorrect as they do not accurately reflect the calculated value after rounding.
What was the mean time for the women who ran the 200m event at the 2008 Olympic Games (times in seconds: 22.33, 22.50, 22.50, 22.61, 22.71, 22.72, 22.83, 23.22)?
- A. 22.50 sec
- B. 22.66 sec
- C. 22.68 sec
- D. 22.77 sec
Correct Answer: C
Rationale: To find the mean time, you need to add all the times (22.33 + 22.50 + 22.50 + 22.61 + 22.71 + 22.72 + 22.83 + 23.22) and then divide by the total number of times (8). This calculation results in a mean time of 22.68 seconds. Choice A, 22.50 sec, is incorrect because it is the time of one of the runners, not the mean time. Choice B, 22.66 sec, and Choice D, 22.77 sec, are also incorrect as they are not the calculated mean of the given times.
What is the mode of the numbers in the distribution shown in the table?
- A. 1
- B. 2
- C. 3
- D. 4
Correct Answer: A
Rationale: The mode of a set of numbers is the value that appears most frequently. In the distribution shown in the table, the number '1' occurs more times than any other number, making it the mode. Choices B, C, and D are incorrect because they do not represent the number that occurs most frequently in the dataset.
Which of the following is listed in order from least to greatest?
- A. -2 3/4, -2 7/8, -1/5, 2/5, 1/8
- B. -1/5, 1/8, 2/5, -2 3/4, -2 7/8
- C. -2 7/8, -2 3/4, -1/5, 1/8, 2/5
- D. 1/8, 2/5, -1/5, -2 7/8, -2 3/4
Correct Answer: C
Rationale: To determine the order from least to greatest, we can convert all fractions and mixed numbers to decimals or use a least common denominator. Converting the fractions in Choice C to decimals, we get -2.875, -2.75, -0.2, 0.125, and 0.4 when reading from left to right. Negative integers with larger absolute values are less than negative integers with smaller absolute values. Therefore, the correct answer is Choice C. Choices A, B, and D are incorrect because they do not present the numbers in the correct order from least to greatest when converted to decimals or compared using common denominators.