Nokea
Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?
- A. $1.75
- B. $2.00
- C. $2.25
- D. $2.50
Correct Answer: C
Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25.
Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.
You may also like to solve these questions
The second midwife allocates 1/2 of her funds to pay an office administrator, plus another 1/10 for office supplies. What is the total fraction of the second midwife's budget that is spent on the office administrator and office supplies?
- A. 3/5
- B. 2/12
- C. 2/20
- D. 1/20
Correct Answer: A
Rationale: To find the total fraction of the second midwife's budget spent on the office administrator and office supplies, add the fractions. The midwife allocates 1/2 of her funds to the office administrator (1/2) and another 1/10 for office supplies. Adding 1/2 and 1/10 gives a total of 3/5. Choice A (3/5) is correct. Choice B (2/12) is incorrect as it simplifies to 1/6, which is not the total fraction. Choice C (2/20) is incorrect as it simplifies to 1/10, which is only the fraction spent on office supplies, not the total. Choice D (1/20) is incorrect as it represents only the fraction spent on office supplies, not the total spent on both the administrator and supplies.
In a study on anorexia, 100 patients participated. Among them, 70% were women, and 10% of the men were overweight as children. How many male patients in the study were not overweight as children?
- A. 3
- B. 10
- C. 27
- D. 30
Correct Answer: C
Rationale: Out of the 100 patients, 30% were men. Since 10% of the men were overweight as children, 90% of the male patients were not overweight. Therefore, the number of male patients not overweight as children can be calculated as 30 (total male patients) x 0.90 = 27. Choices A, B, and D are incorrect because they do not accurately calculate the number of male patients who were not overweight as children based on the given information.
Within a nursing program, 25% of the class wanted to work with infants, 60% wanted to work with the elderly, 10% wanted to assist general practitioners, and the rest were undecided. What fraction of the class wanted to work with the elderly?
- A. 1/4
- B. 1/10
- C. 3/5
- D. 1/20
Correct Answer: C
Rationale: To find the fraction of the class wanting to work with the elderly, we convert the percentage to a fraction. 60% can be written as 60/100, which simplifies to 3/5. Therefore, 3/5 of the class wanted to work with the elderly. Choice A (1/4), choice B (1/10), and choice D (1/20) do not represent the fraction of the class wanting to work with the elderly, making them incorrect.
A patient requires a 20% decrease in medication dosage. Their current dosage is 400 mg. What will their dosage be after the decrease?
- A. 60 mg
- B. 80 mg
- C. 120 mg
- D. 320 mg
Correct Answer: B
Rationale: To calculate a 20% decrease of 400 mg, you multiply 400 mg by 0.20 to get 80 mg. Subtracting 80 mg from the current dosage of 400 mg results in a new dosage of 320 mg. Choice A is incorrect because it miscalculates the decrease. Choice C is incorrect as it represents a 20% increase instead of a decrease. Choice D is incorrect as it represents the initial dosage, not the reduced dosage.
During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?
- A. shifts = 20 + 3 + 1/2
- B. shifts = (20)(3)(1/2)
- C. shifts = (20)(3) + 1/2
- D. shifts = 20 + (3)(1/2)
Correct Answer: B
Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.