Nokea
Almost all (99%) of the calcium in the body is used for?
- A. regulating the transmission of nerve impulses
- B. providing energy for cells
- C. providing rigidity for the bones
- D. regulating muscle contraction
Correct Answer: C
Rationale: The correct answer is C: providing rigidity for the bones. Almost all of the calcium in the body is utilized for maintaining the strength and structure of bones and teeth. Calcium plays a crucial role in skeletal health by providing rigidity and support to the skeletal system. Choices A, B, and D are incorrect because while calcium is essential for various physiological functions like nerve transmission, cell energy production, and muscle contraction, the majority of calcium in the body is primarily allocated for bone health.
You may also like to solve these questions
Can soluble fibers be fermented by gut bacteria?
- A. TRUE
- B. FALSE
Correct Answer: A
Rationale: Soluble fibers can indeed be fermented by gut bacteria in the large intestine, leading to the production of beneficial short-chain fatty acids. This fermentation process is important for gut health and provides various health benefits. Therefore, the statement is true. Choice B is incorrect as it contradicts the known scientific fact that soluble fibers can be broken down by gut bacteria through fermentation.
A mother asks about healthy snacks for her three children under 4 years old. All are wise choices the dental hygienist can recommend, except one. Which is the exception?
- A. Low-fat milk or yogurt
- B. Whole-grain cereals
- C. Raw vegetable sticks
- D. Nuts and seeds
Correct Answer: D
Rationale: Nuts and seeds pose a choking hazard for children under 4 years old, making them an unsafe snack choice for young children. While low-fat milk or yogurt, whole-grain cereals, and raw vegetable sticks are healthy snack options suitable for children under 4 years old, nuts and seeds should be avoided due to the risk of choking, especially in young children who may not have fully developed chewing abilities.
What laboratory value would be considered a high-risk measure for coronary heart disease assessment?
- A. triglycerides > 150 mg/dL
- B. BMI > 31
- C. LDL cholesterol < 128 mg/dL
- D. blood pressure of 128/82 mmHg
Correct Answer: B
Rationale: The correct answer is B: BMI > 31. A BMI over 31 is considered a high-risk factor for coronary heart disease as it indicates obesity, which is strongly linked to cardiovascular issues. Triglycerides > 150 mg/dL (choice A) can contribute to heart disease risk but are not as specific as BMI in assessing overall risk. LDL cholesterol < 128 mg/dL (choice C) is actually a desirable level, indicating lower risk. A blood pressure of 128/82 mmHg (choice D) is within normal range and not a high-risk measure specifically for coronary heart disease.
What is the end product of lipid digestion?
- A. fatty acid
- B. sucrose
- C. monosaccharide
- D. amino acid
Correct Answer: A
Rationale: The correct answer is A, fatty acid. During the process of lipid digestion, triglycerides are broken down into fatty acids and glycerol. These end products are then absorbed into the bloodstream or lymphatic system for further processing. Choices B, C, and D are incorrect because sucrose is a disaccharide, monosaccharide is a simple sugar unit, and amino acid is a building block of proteins, not the end product of lipid digestion.
How many diet-related major risk factors for coronary heart disease does Mrs. Winslow have?
- A. 1
- B. 4
- C. 2
- D. 3
Correct Answer: B
Rationale: Mrs. Winslow has four major diet-related risk factors for coronary heart disease: high total cholesterol, high LDL cholesterol, high triglycerides, and low HDL cholesterol. Choice A is incorrect because there are more than one risk factor present. Choices C and D are incorrect as they do not account for the total number of diet-related major risk factors identified.