Nokea
The patient’s serum creatinine level is 7 mg/dL. The expected BUN level should be
- A. 1 to 2 mg/dL.
- B. 7 to 14 mg/dL.
- C. 10 to 20 mg/dL.
- D. 20 to 30 mg/dL.
Correct Answer: C
Rationale: The correct answer is C (10 to 20 mg/dL). In conditions where the serum creatinine level is elevated (7 mg/dL in this case), the BUN level is expected to also be elevated due to impaired kidney function. BUN levels are typically around 10-20 mg/dL, so this range is the most appropriate given the elevated creatinine level.
Choice A (1 to 2 mg/dL) is too low and would not be expected with a creatinine level of 7 mg/dL. Choice B (7 to 14 mg/dL) is a bit low for such a high creatinine level. Choice D (20 to 30 mg/dL) is too high as it exceeds the typical range for BUN levels. Therefore, choice C is the most appropriate range based on the given information.
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Mechanisms for development of diabetes insipidus include which of the following? (Select all that apply.)
- A. ADH deficiency
- B. ADH excess
- C. ADH insensitivity
- D. ADH replacement therapy
Correct Answer: A
Rationale: The correct answer is A: ADH deficiency. Diabetes insipidus is caused by a deficiency of antidiuretic hormone (ADH), leading to excessive urine production and thirst. ADH is responsible for regulating water reabsorption in the kidneys. When ADH levels are low or absent, the kidneys cannot concentrate urine effectively, resulting in excessive urine output.
Explanation for why other choices are incorrect:
B: ADH excess would not lead to diabetes insipidus, as it would result in increased water reabsorption and concentrated urine.
C: ADH insensitivity refers to a condition where the body does not respond to ADH, but it does not cause diabetes insipidus.
D: ADH replacement therapy is actually a treatment for diabetes insipidus, not a mechanism for its development.
Which of the following would be seen in a patient with myxedema coma?
- A. Decreased reflexes
- B. Hyperthermia
- C. Hyperventilation
- D. Tachycardia
Correct Answer: A
Rationale: The correct answer is A: Decreased reflexes. In myxedema coma, a severe form of hypothyroidism, patients often present with decreased mental status, hypothermia, and bradycardia. Decreased reflexes are a common neurological manifestation due to the slowing of metabolic processes and the central nervous system depression associated with this condition. Hyperthermia (B) is not typically seen in myxedema coma, as patients usually have low body temperature. Hyperventilation (C) is also unlikely, as respiratory depression is more common. Tachycardia (D) is incorrect because bradycardia is more characteristic of myxedema coma.
The patient is in a progressive care unit following arteriovenous fistula implantation in his left upper arm, and is due to have blood drawn with his next set of vital signs and assessment. When the nurse assesses the patient, the nurse should
- A. draw blood from the left arm.
- B. take blood pressures from the left arm.
- C. start a new intravenous line in the left lower arm.
- D. auscultate the left arm for a bruit and palpate for a thrill.
Correct Answer: D
Rationale: The correct answer is D. Auscultating the left arm for a bruit and palpating for a thrill post arteriovenous fistula implantation is crucial to assess the patency and functionality of the fistula. A bruit indicates turbulent blood flow, while a thrill signifies the presence of a strong pulse through the fistula. These assessments help identify any complications like stenosis or thrombosis. Drawing blood or taking blood pressures from the arm with the fistula can lead to inaccurate results or damage the fistula. Starting a new IV line in the left lower arm is unnecessary and not relevant to monitoring the arteriovenous fistula.
The patient’s potassium level is 0 mEq/L. Besides dialysis, which of the following actually reduces plasma potassium levels and total body potassium content safely in a patient with renal dysfunction?
- A. Sodium polystyrene sulfonate
- B. Sodium polystyrene sulfonate with sorbitol
- C. Regular insulin
- D. Calcium gluconate
Correct Answer: A
Rationale: The correct answer is A: Sodium polystyrene sulfonate. It works by exchanging sodium ions for potassium ions in the colon, leading to potassium excretion. A is the safest option without the risk of causing hypernatremia or intestinal necrosis like B. Regular insulin (C) may cause hypoglycemia and is not as effective as A in reducing potassium levels. Calcium gluconate (D) does not directly reduce potassium levels and is used for treating hyperkalemia-related cardiac toxicity.
The patient is admitted with complaints of general malaise and fatigue, along with a decreased urinary output. The patient’s urinalysis shows coarse, muddy brown granular casts and hematuria. The nurse determines that the patient has:
- A. acute kidney injury from a prerenal condition.
- B. acute kidney injury from postrenal obstruction.
- C. intrarenal disease, probably acute tubular necrosis.
- D. a urinary tract infection.
Correct Answer: C
Rationale: The correct answer is C: intrarenal disease, probably acute tubular necrosis. The presence of coarse, muddy brown granular casts and hematuria in the urinalysis indicates damage to the renal tubules, which is characteristic of acute tubular necrosis. This condition is a type of intrarenal disease where there is direct damage to the kidney tubules, leading to decreased urinary output and symptoms like malaise and fatigue. Prerenal and postrenal conditions do not typically present with granular casts and hematuria, making choices A and B incorrect. Urinary tract infection is also unlikely to cause the specific findings seen in this case, ruling out choice D. Therefore, choice C is the most appropriate based on the urinalysis results and clinical presentation.