Nokea
Unlike eukaryotic cytoplasm, the prokaryotic one is:
- A. More complex
- B. Simpler
- C. There is no difference in the structure
- D. None of the above
Correct Answer: B
Rationale: The correct answer is B: Simpler. Prokaryotic cytoplasm is simpler than eukaryotic cytoplasm because prokaryotic cells lack membrane-bound organelles such as a nucleus, mitochondria, and endoplasmic reticulum that are present in eukaryotic cells. Prokaryotic cytoplasm contains fewer components and structures compared to eukaryotic cytoplasm, making it less complex. Therefore, the prokaryotic cytoplasm is simpler in structure. Choices A, C, and D are incorrect because prokaryotic cytoplasm is not more complex than eukaryotic cytoplasm, there is a clear difference in structure between prokaryotic and eukaryotic cytoplasm, and the statement "None of the above" is not accurate as the correct answer is B.
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A lymph node punctate of a patient with suspected protozoa disease was examined. Examination of the stained specimen (Romanovsky's stain) revealed some crescent bodies with pointed end, blue cytoplasm and red nucleus. What protozoan were revealed in the smears?
- A. Toxoplasmas
- B. Malarial plasmodiums
- C. Dermotropic leishmania
- D. Viscerotropic leishmania
Correct Answer: B
Rationale: The correct answer is B: Malarial plasmodiums. The description of crescent bodies with a pointed end, blue cytoplasm, and red nucleus corresponds to the characteristics of Plasmodium species seen in Romanovsky's stain. Plasmodium species are known to cause malaria and have distinct features like the ones described.
Incorrect choices:
A: Toxoplasmas - Toxoplasma gondii typically appear as tachyzoites or bradyzoites under staining, not crescent bodies.
C: Dermotropic leishmania - Leishmania species appear as amastigotes in tissue smears, not crescent bodies.
D: Viscerotropic leishmania - Similar to choice C, Leishmania species do not typically present as crescent bodies in stained specimens.
Growth of bacteria is a result of:
- A. Air consumption
- B. Water adsorption
- C. Enzyme production
- D. Radio isotopes
Correct Answer: B
Rationale: The growth of bacteria is a result of water adsorption because water is essential for various metabolic processes within the bacterial cells, such as nutrient uptake, energy production, and waste removal. Water serves as a medium for chemical reactions to occur and provides structural support to the bacteria. Without sufficient water, bacteria cannot thrive and reproduce.
A: Air consumption is incorrect because while bacteria may require oxygen for respiration, it is not the primary factor for their growth.
C: Enzyme production is incorrect because enzymes are important for various cellular functions but do not directly influence bacterial growth.
D: Radio isotopes are incorrect as they are not essential for bacterial growth and can even be harmful to bacterial cells.
What is the function of bacterial fimbriae?
- A. Adhesion to surfaces
- B. DNA replication
- C. Protein synthesis
- D. Flagella movement
Correct Answer: A
Rationale: The correct answer is A: Adhesion to surfaces. Bacterial fimbriae are hair-like appendages that help bacteria attach to surfaces, such as host cells or medical devices. This adhesion is crucial for colonization and infection. DNA replication (B) occurs in the cell's nucleus, not on the surface. Protein synthesis (C) happens inside the cell, not on the fimbriae. Flagella movement (D) is the function of flagella, not fimbriae.
Which bacteria are capable of producing endospores?
- A. Staphylococcus aureus
- B. Clostridium botulinum
- C. Escherichia coli
- D. Neisseria gonorrhoeae
Correct Answer: B
Rationale: The correct answer is B: Clostridium botulinum. This bacterium belongs to the Clostridium genus, known for its ability to produce endospores. Endospores are dormant, resistant structures that help bacteria survive harsh conditions. Staphylococcus aureus (A), Escherichia coli (C), and Neisseria gonorrhoeae (D) do not produce endospores. Staphylococcus aureus is a gram-positive bacterium known for causing various infections, but it does not form endospores. Escherichia coli is a gram-negative bacterium commonly found in the intestines of humans and animals, but it does not produce endospores. Neisseria gonorrhoeae is a gram-negative bacterium that causes the sexually transmitted infection gonorrhea, but it also does not form endospores.
Which of the following methods can be used for diagnosis of respiratory tract infections
- A. Culture of samples from the respiratory tract
- B. Immunofluorescence
- C. PCR
- D. All are correct
Correct Answer: D
Rationale: The correct answer is D: All are correct. Culture of samples from the respiratory tract can identify specific pathogens, Immunofluorescence can detect viral antigens, and PCR can amplify and detect specific DNA/RNA sequences. Using all methods together provides a comprehensive approach for diagnosing respiratory tract infections. Culture alone may miss fastidious organisms, Immunofluorescence has limitations in sensitivity, and PCR requires specific primers. Therefore, combining these methods increases the likelihood of accurate diagnosis by covering a range of pathogens and improving sensitivity and specificity.