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Which of the following describes a graph that represents a proportional relationship?
- A. The graph has a slope of 2,500 and a y-intercept of 250
- B. The graph has a slope of 1,500 and a y-intercept of -150
- C. The graph has a slope of 2,000 and a y-intercept of 0
- D. The graph has a slope of -1,800 and a y-intercept of -100
Correct Answer: C
Rationale: A graph that has a y-intercept of 0 indicates a proportional relationship because the starting value is 0, and no amount is added to or subtracted from the term containing the slope. In this case, choice C is correct as it has a y-intercept of 0, which aligns with the characteristics of a proportional relationship. Choices A, B, and D have non-zero y-intercepts, indicating a starting value other than 0, which does not represent a proportional relationship.
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If Hannah spends at least $16 on 4 packages of coffee, which of the following inequalities represents the possible costs?
- A. 16 ≥ 4p
- B. 16 < 4p
- C. 16 > 4p
- D. 16 ≤ 4p
Correct Answer: D
Rationale: To represent the relationship between the number of packages of coffee and the minimum cost, the inequality can be written as 4p ≥ 16 (cost is at least $16). This inequality can also be expressed as 16 ≤ 4p, which reads as the cost being less than or equal to $16. Therefore, the correct answer is D. Choice A (16 ≥ 4p) implies that the cost can be greater than or equal to $16, which does not align with the statement that Hannah spends at least $16. Choice B (16 < 4p) suggests that the cost is less than $16, which contradicts the given information. Choice C (16 > 4p) indicates that the cost is greater than $16, which is not accurate based on the scenario provided.
Pernell received the following scores on five exams: 81, 92, 87, 89, and 94. What is the approximate average of these scores?
- A. 81
- B. 84
- C. 89
- D. 91
Correct Answer: C
Rationale: To calculate the average of Pernell's scores, add all the scores together and then divide by the number of scores.
(81 + 92 + 87 + 89 + 94) = 443.
Now, divide 443 by 5:
443 · 5 = 89, which is the average score.
There are 80 mg in 0.8 mL of Acetaminophen Concentrated Infant Drops. If the proper dosage for a four-year-old child is 240 mg, how many milliliters should the child receive?
- A. 0.8 mL
- B. 1.6 mL
- C. 2.4 mL
- D. 3.2 mL
Correct Answer: C
Rationale: To find out how many milliliters the child should receive, divide the total required dosage of 240 mg by the concentration of the medication, which is 80 mg per 0.8 mL. 240 mg · 80 mg/mL = 3 mL. Since each dose is 0.8 mL, the total dosage for the child would be 3 doses x 0.8 mL per dose = 2.4 mL. Therefore, the correct answer is 2.4 mL. Choice A (0.8 mL) is the concentration of the medication, not the total dose. Choices B (1.6 mL) and D (3.2 mL) are incorrect calculations that do not consider the concentration of the medication and the total required dosage correctly.
Simplify the following expression:
- A. 1 9/16
- B. 1 1/4
- C. 2 1/8
- D. 2
Correct Answer: A
Rationale: To simplify the given expression, start by performing the division first: (2/3) · (4/15) = (2/3) (15/4) = 30/12 = 5/2. Next, multiply this result by 5/8: 5/2 5/8 = 25/16 = 1 9/16. Therefore, the correct answer is A. Choice B (1 1/4) is incorrect as it does not match the simplified result. Choice C (2 1/8) is incorrect as it does not represent the simplified expression. Choice D (2) is incorrect as it does not account for the fractions in the original expression.
Given the double bar graph shown below, which of the following statements is true?
- A. Group A is negatively skewed, while Group B is approximately normal.
- B. Group A is positively skewed, while Group B is approximately normal.
- C. Group A is approximately normal, while Group B is negatively skewed.
- D. Group A is approximately normal, while Group B is positively skewed.
Correct Answer: B
Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.