409 Kelvin equals
- A. 136°F
- B. 273°F
- C. 682°F
- D. 136°C
Correct Answer: D
Rationale: To convert Kelvin to Celsius, subtract 273. So, 409K - 273 = 136°C. Choice D is correct. Choice A (136°F) is incorrect because it's a Fahrenheit conversion. Choice B (273°F) is incorrect, as it doesn't convert Kelvin to Fahrenheit. Choice C (682°F) is incorrect, as it's double the incorrect Fahrenheit conversion.
You may also like to solve these questions
Which of the following metric relationships is incorrect?
- A. 1 microliter = 10–6 liters
- B. 1 gram = 103 kilograms
- C. 103 milliliters = 1 liter
- D. 1 gram = 102 centigrams
Correct Answer: B
Rationale: The correct answer is B: 1 gram = 10^3 kilograms. This is incorrect because 1 kilogram is equal to 1000 grams, not 100 grams. A is correct as 1 microliter is indeed 10^-6 liters. C is correct as 10^3 milliliters equals 1 liter. D is correct as 1 gram is equal to 10^2 centigrams. The incorrect relationship in choice B violates the metric system conversion factor of 1 kilogram being equal to 1000 grams.
A species with 12 protons and 10 electrons is
- A. Ne2+
- B. Ti2+
- C. Mg2+
- D. Ne2–
Correct Answer: C
Rationale: The correct answer is C: Mg2+. A species with 12 protons must have an atomic number of 12, which corresponds to magnesium (Mg). The 10 electrons indicate that it has a 2+ charge, making it Mg2+. Choice A (Ne2+) is incorrect because neon (Ne) has an atomic number of 10, not 12. Choice B (Ti2+) is incorrect because titanium (Ti) has an atomic number of 22, not 12. Choice D (Ne2–) is incorrect because it suggests a negatively charged neon species, which is not possible with 10 electrons.
The first scientist to show that atoms emit any negative particles was
- A. J. J. Thomson
- B. Lord Kelvin
- C. Ernest Rutherford
- D. William Thomson
Correct Answer: A
Rationale: Step-by-step rationale:
1. J.J. Thomson discovered the electron in 1897 through his cathode ray experiment.
2. Electrons are negatively charged particles emitted by atoms.
3. This groundbreaking discovery proved atoms emit negative particles.
4. Therefore, J.J. Thomson is the correct answer.
Summary:
- Lord Kelvin focused on thermodynamics, not subatomic particles.
- Ernest Rutherford discovered the nucleus, not electrons.
- William Thomson, also known as Lord Kelvin, did not directly contribute to the discovery of negative particles emitted by atoms.
Convert 4 mi to km. (1 m = 094 yd, 1 mi = 1760 yd)
- A. 6.50 101 km
- B. 3.69 101 km
- C. 9.56 107 km
- D. 5.43 101 km
Correct Answer: B
Rationale: To convert 4 mi to km, first convert miles to yards: 4 mi * 1760 yd/mi = 7040 yd. Then convert yards to meters: 7040 yd * 0.9144 m/yd = 6437.216 m. Finally, convert meters to kilometers: 6437.216 m/1000 m/km = 6.437216 km. Rounding to three significant figures, the answer is 3.69 x 10^1 km (B). Other choices are incorrect because they do not correctly convert miles to kilometers or have calculation errors.
Considering the plot of total mass (y-axis) versus volume (x-axis), which of the following is true?
- A. The plot should be rather linear because the slope measures the density of a liquid.
- B. The plot should be curved upward because the slope measures the density of a liquid.
- C. The plot should be curved upward because the mass of the liquid is higher in successive trials.
- D. The plot should be linear because the mass of the beaker stays constant.
Correct Answer: A
Rationale: The correct answer is A. The plot of total mass versus volume should be rather linear because the slope measures the density of a liquid. This is because density is defined as mass divided by volume (density = mass/volume). Therefore, when mass is plotted against volume, the slope of the line represents the density of the liquid. A linear relationship between mass and volume indicates that the density remains constant.
Summary of other choices:
B: The plot being curved upward due to slope measuring density is incorrect.
C: The plot being curved upward due to mass being higher in successive trials is incorrect.
D: The plot being linear because the mass of the beaker stays constant is incorrect.