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A client is receiving an epidural block with an opioid analgesic. The nurse should monitor for which of the following findings as an adverse effect of the medication?
- A. Hypotension
- B. Polyuria
- C. Bilateral crackles
- D. Hyperglycemia
Correct Answer: C
Rationale: The correct answer is C: Bilateral crackles. Bilateral crackles indicate respiratory complications, which can occur as an adverse effect of an epidural block with opioid analgesics. Hypotension (Choice A) is a common side effect of epidural opioids but is not typically monitored via crackles. Polyuria (Choice B) is excessive urination and is not directly associated with epidural blocks. Hyperglycemia (Choice D) is high blood sugar levels and is not a typical adverse effect of epidural opioids.
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Females with Turner syndrome:
- A. possess more thymine than cytosine.
- B. are taller than average.
- C. produce little estrogen.
- D. are more likely to give birth to twins.
Correct Answer: C
Rationale: Turner syndrome is a chromosomal disorder in females characterized by short stature and underdeveloped ovaries, resulting in low estrogen production. This leads to symptoms such as delayed puberty and infertility. Choice A is incorrect because the chromosomal abnormality in Turner syndrome does not affect the thymine-cytosine ratio. Choice B is incorrect as females with Turner syndrome are typically shorter than average. Choice D is incorrect as Turner syndrome does not increase the likelihood of giving birth to twins.
A client is experiencing preterm labor and has a prescription for 4 doses of dexamethasone 6 mg IM every 12 hours. The available concentration is dexamethasone 10 mg/mL. How many mL of dexamethasone should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use trailing zero.)
- A. 0.6 mL
- B. ---
- C. ---
- D. ---
Correct Answer: A
Rationale: Calculation: (6 mg/dose) / (10 mg/mL) = 0.6 mL per dose. The correct answer is 0.6 mL. This calculation is obtained by dividing the dose needed (6 mg) by the concentration available (10 mg/mL). The resulting value is 0.6 mL per dose. Choices B, C, and D are not applicable as the correct answer has been calculated accurately.
A client who has mild preeclampsia and will be caring for herself at home during the last 2 months of pregnancy is receiving teaching from a healthcare provider. Which statement by the client indicates an understanding of the teaching?
- A. "I will count baby's kicks every other day."
- B. "I will alternate the arm used to check my blood pressure."
- C. "I will consume 50 grams of protein daily."
- D. ---
Correct Answer: B
Rationale: The correct answer is B. Alternating arms for blood pressure checks ensures more accurate readings and helps monitor preeclampsia. Option A, counting baby's kicks every other day, is not specific to managing preeclampsia. Option C, consuming 50 grams of protein daily, is important for a healthy diet during pregnancy but does not directly relate to preeclampsia management.
A healthcare professional is caring for a client who is 14 weeks of gestation. At which of the following locations should the healthcare professional place the Doppler device when assessing the fetal heart rate?
- A. Midline 2 to 3 cm (0.8 to 1.2 in) above the symphysis pubis
- B. Left Upper Abdomen
- C. Two fingerbreadths above the umbilicus
- D. Lateral at the Xiphoid Process
Correct Answer: A
Rationale: At 14 weeks of gestation, the uterus is still relatively low in the abdomen. Placing the Doppler midline 2 to 3 cm above the symphysis pubis is appropriate for assessing the fetal heart rate. This location allows for better detection of the fetal heart tones as the uterus is at a lower position during this stage of pregnancy. Placing the Doppler on the left upper abdomen would not be ideal at 14 weeks gestation as the uterus is not yet at that level. Placing it two fingerbreadths above the umbilicus or lateral at the xiphoid process would also not be accurate for locating the fetal heart rate at this stage of gestation.
Humans begin life as a single cell that divides repeatedly. This cell is known as a(n):
- A. zygote.
- B. gonadotrope.
- C. embryo.
- D. chromaffin.
Correct Answer: A
Rationale: A zygote is the correct answer. It is the initial cell formed when a sperm cell fertilizes an egg cell, marking the beginning of human development. Choice B, gonadotrope, is incorrect as it refers to a type of hormone-secreting cell in the pituitary gland. Choice C, embryo, is incorrect as it is the stage of development after the zygote has implanted into the uterine wall and undergone initial cell divisions. Choice D, chromaffin, is incorrect as it refers to cells found in the adrenal medulla that produce and store catecholamines.