Nokea
A nurse is caring for a newborn who is 6 hours old and has a bedside glucometer reading of 65 mg/dL. The newborn's mother has type 2 diabetes mellitus. Which of the following actions should the nurse take?
- A. Obtain a blood sample for a serum glucose level
- B. Feed the newborn immediately
- C. Administer 50 mL of dextrose solution IV
- D. Reassess the blood glucose level prior to the next feeding
Correct Answer: D
Rationale: A bedside glucometer reading of 65 mg/dL is within the normal range for a newborn. Reassessing the blood glucose level prior to the next feeding ensures ongoing monitoring without unnecessary intervention. Obtaining a blood sample for a serum glucose level (Choice A) is not necessary as the initial reading is normal. Feeding the newborn immediately (Choice B) may not be indicated and could lead to unnecessary interventions. Administering dextrose solution IV (Choice C) is not warranted as the glucose level is within the normal range and does not require immediate correction.
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What is the purpose of amniocentesis?
- A. To induce abortion
- B. To detect genetic abnormalities in the fetus
- C. To determine the baby's gender
- D. To monitor fetal growth
Correct Answer: B
Rationale: Amniocentesis is a diagnostic procedure used to detect genetic abnormalities in the fetus, such as chromosomal disorders like Down syndrome. It is not performed to induce abortion. The primary purpose of amniocentesis is to assess the genetic health of the fetus, not to determine the baby's gender (Choice C). While amniocentesis can provide information about the baby's health and development, it is not primarily used for monitoring fetal growth (Choice D). Therefore, the correct answer is B.
Before meiosis, a sperm cell:
- A. contains 46 chromosomes.
- B. contains two X chromosomes.
- C. is significantly larger than an egg cell.
- D. contains both an X and a Y chromosome.
Correct Answer: A
Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.
After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.
- A. reductions
- B. expulsions
- C. conceptions
- D. mutations
Correct Answer: D
Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.
A client at 20 weeks of gestation has trichomoniasis. Which of the following findings should the nurse expect?
- A. Thick, White Vaginal Discharge
- B. Urinary Frequency
- C. Vulvar Lesions
- D. Malodorous Discharge
Correct Answer: D
Rationale: Malodorous discharge is a common symptom of trichomoniasis caused by the Trichomonas vaginalis parasite. It is typically described as frothy, greenish-yellow, and malodorous. Choices A, B, and C are incorrect findings associated with other conditions. Thick, white vaginal discharge is more characteristic of a yeast infection; urinary frequency may be seen in urinary tract infections; and vulvar lesions are commonly seen in herpes simplex virus infections.
A 25-year-old gravida 3, para 2 client gave birth to a 9-pound, 7-ounce boy 4 hours ago after augmentation of labor with oxytocin (Pitocin). She presses her call light and asks for her nurse right away, stating 'I'm bleeding a lot.' What is the most likely cause of postpartum hemorrhage in this client?
- A. Retained placental fragments.
- B. Unrepaired vaginal lacerations.
- C. Uterine atony.
- D. Puerperal infection.
Correct Answer: C
Rationale: Uterine atony is the most likely cause of bleeding 4 hours after delivery, especially after delivering a macrosomic infant and augmenting labor with oxytocin. Uterine atony is characterized by the inability of the uterine muscles to contract effectively after childbirth, leading to excessive bleeding. The other options, such as retained placental fragments (A), unrepaired vaginal lacerations (B), and puerperal infection (D), are less likely causes of postpartum hemorrhage in this scenario. Retained placental fragments can cause bleeding, but this typically presents earlier than 4 hours postpartum. Unrepaired vaginal lacerations would likely be evident sooner and not typically result in significant bleeding. Puerperal infection is not a common cause of immediate postpartum hemorrhage unless there are other signs of infection present.