A nursing student wants to know why clients with chronic obstructive pulmonary disease tend to be polycythemic. What response by the nurse instructor is best?
- A. It is due to side effects of medications for bronchodilation.
- B. It is from overactive bone marrow in response to chronic disease.
- C. It combats the anemia caused by an increased metabolic rate.
- D. It compensates for tissue hypoxia caused by lung disease.
Correct Answer: D
Rationale: The correct answer is D. In chronic obstructive pulmonary disease (COPD), the lungs are unable to efficiently exchange oxygen and carbon dioxide, leading to tissue hypoxia. The body compensates for this by producing more red blood cells (polycythemia) to increase oxygen-carrying capacity. This helps deliver more oxygen to tissues.
Choice A is incorrect because medications for bronchodilation do not directly cause polycythemia. Choice B is incorrect because overactive bone marrow is not the primary reason for polycythemia in COPD. Choice C is incorrect because polycythemia in COPD is not a response to combat anemia but rather to address tissue hypoxia.
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A patient with pancytopenia has a bone marrow aspiration from the left posterior iliac crest. Which action would be important for the nurse to take after the procedure?
- A. Elevate the head of the bed to 45 degrees.
- B. Apply a sterile 2-inch gauze dressing to the site.
- C. Use a half-inch sterile gauze to pack the wound.
- D. Have the patient lie on the left side for 1 hour.
Correct Answer: D
Rationale: The correct answer is D: Have the patient lie on the left side for 1 hour. This position helps prevent bleeding by applying pressure to the site. Elevating the head of the bed (A) is not necessary for this procedure. Applying a 2-inch gauze dressing (B) may disrupt the site and increase the risk of bleeding. Using half-inch sterile gauze to pack the wound (C) is not recommended for bone marrow aspiration sites as it can lead to infection.
You have a new 7-year-old female patient with a WBC count of 6,000/mm3, hemoglobin of 7.2 g/dL, and platelet count of 30,000/mm3. A bone marrow aspirate reveals 14% blasts with a monocytic morphologic appearance that are surface marker positive for CD33. You receive a call from the fluorescence in situ hybridization (FISH) lab that the bone marrow is positive for KMT2A rearrangement in 68% of cells. Your staff asks whether this represents a diagnosis of acute leukemia in the current classification scheme for this type of hematologic malignancy. What would you say?
- A. No, because for a diagnosis of acute leukemia you must have 30% or more blasts in the marrow.
- B. No, because for a diagnosis of acute leukemia you must have 20% or more blasts in the marrow.
- C. No, because the cytogenetics do not include +21, monosomy 7, or trisomy 8.
- D. Yes, because the FISH is positive for KMT2A rearrangement.
Correct Answer: D
Rationale: The correct answer is D: Yes, because the FISH is positive for KMT2A rearrangement. The presence of KMT2A rearrangement in 68% of cells indicates a specific genetic abnormality associated with acute leukemia. This abnormality is a known marker for acute myeloid leukemia (AML) with recurrent genetic abnormalities. The percentage of blasts in the bone marrow (14%) may not meet the traditional criteria for a diagnosis of acute leukemia based on blast percentage alone, but the presence of KMT2A rearrangement overrides this requirement in this case. Choices A and B are incorrect because blast percentage alone is not the sole determinant of a diagnosis of acute leukemia when specific genetic abnormalities are present. Choice C is incorrect because while the absence of specific cytogenetic abnormalities may be relevant for some cases, the presence of KMT2A rearrangement is sufficient to support a diagnosis of acute leukemia in this context.
After seven days of treatment with sulfonamides, a patient's hemoglobin had decreased from 14.7 gm/100ml to 10gm/100ml. The most likely cause of hemolysis in this patient is
- A. Sickle cell disease
- B. Thalassemia minor
- C. Hereditary spherocytosis
- D. Glucose 6-phosphate dehydrogenase deficiency (G6PD)
Correct Answer: D
Rationale: The correct answer is D: Glucose 6-phosphate dehydrogenase deficiency (G6PD). Sulfonamides can trigger hemolysis in patients with G6PD deficiency due to oxidative stress on red blood cells. G6PD enzyme deficiency impairs the ability of red blood cells to combat oxidative damage, leading to hemolysis. In this case, the patient's hemoglobin decreased significantly after sulfonamide treatment, indicating red blood cell destruction. The other choices (A: Sickle cell disease, B: Thalassemia minor, C: Hereditary spherocytosis) are not directly associated with sulfonamide-induced hemolysis and would not explain the observed decrease in hemoglobin levels after treatment.
A patient with leukemia has developed stomatitis and is experiencing a nutritional deficit. An oral anesthetic has consequently been prescribed. What health education should the nurse provide to the patient?
- A. Chew with care to avoid inadvertently biting the tongue.
- B. Use the oral anesthetic 1 hour prior to meal time.
- C. Brush teeth before and after eating.
- D. Swallow slowly and deliberately.
Correct Answer: A
Rationale: The correct answer is A: Chew with care to avoid inadvertently biting the tongue. Stomatitis causes inflammation in the mouth, making it painful to eat. By chewing carefully, the patient can prevent accidentally biting the tongue or cheek, which can worsen the pain. Using the oral anesthetic before meals (choice B) may provide some relief, but the key is to prevent further injury. Brushing teeth before and after eating (choice C) and swallowing slowly (choice D) do not directly address the issue of preventing accidental bites and are not as essential for managing stomatitis.
You examine a 10-year-old boy with severe aplastic anemia. He has no dysmorphic features and is at the 50th percentile for height and weight. Family history includes a sister with aplastic anemia unresponsive to anti-human thymocyte globulin (ATG) and cyclosporine who died early in the course of an unrelated donor hematopoietic stem cell transplant complicated by severe mucositis and transplant-related organ toxicities. There are no other siblings. A cousin died of acute myeloid leukemia at age 5 years. A peripheral blood sample test for Fanconi anemia is negative with no increased chromosomal breaks in response to diepoxylbutane or mitomycin C. Which of the following is the most important next step in management?
- A. Administer ATG and cyclosporine.
- B. Search for a donor for matched unrelated transplant.
- C. Send a bone marrow aspirate for Fanconi anemia testing.
- D. Send a skin fibroblast culture for Fanconi anemia testing.
Correct Answer: D
Rationale: The correct answer is D: Send a skin fibroblast culture for Fanconi anemia testing. This is the most important next step in management because the patient's history, including a family member with aplastic anemia and a cousin with leukemia, raises suspicion for a genetic disorder like Fanconi anemia. Testing skin fibroblasts for Fanconi anemia can help confirm or rule out this diagnosis. Administering ATG and cyclosporine (choice A) may not be effective if the underlying cause is a genetic disorder. Searching for a donor for matched unrelated transplant (choice B) is premature without confirming the diagnosis. Sending a bone marrow aspirate for Fanconi anemia testing (choice C) may not yield accurate results as the peripheral blood sample test was negative, making skin fibroblast culture the preferred choice.