TEAS version 7 quizlet science Related

Review TEAS version 7 quizlet science related questions and content

A spring with a spring constant of 100 N/m is stretched 0.2 m from its equilibrium position. What is the potential energy stored in the spring?

  • A. 2 J
  • B. 4 J
  • C. 8 J
  • D. 20 J
Correct Answer: C

Rationale: The potential energy stored in a spring is given by the formula \(PE = \frac{1}{2}kx^2\), where \(k\) is the spring constant and \(x\) is the displacement from the equilibrium position. Substituting the given values, we get \(PE = \frac{1}{2} \times 100 \times (0.2)^2 = 8\) J.