Nokea
Following a traumatic delivery, an infant receives an initial Apgar score of 3. Which intervention is most important for the nurse to implement?
- A. Page the pediatrician STAT
- B. Continue resuscitative efforts
- C. Repeat the Apgar assessment in 5 minutes
- D. Inform the parents of the infant's condition
Correct Answer: B
Rationale: In a situation where an infant receives a low Apgar score of 3 following a traumatic delivery, the most crucial intervention for the nurse to implement is to continue resuscitative efforts. A low Apgar score indicates that the newborn is in distress and requires immediate medical attention to support breathing, heart rate, muscle tone, reflex irritability, and color. Continuing resuscitative efforts is essential to provide life-saving interventions promptly. Paging the pediatrician may cause a delay in crucial interventions, repeating the Apgar assessment in 5 minutes is not appropriate as immediate action is needed to stabilize the infant, and informing parents should not take precedence over providing immediate medical care to the newborn.
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Monozygotic (MZ) twins share _________ percent of their genes.
- A. 100
- B. 75
- C. 50
- D. 25
Correct Answer: A
Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.
Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:
- A. a carrier of the recessive gene that causes the disease.
- B. susceptible to the disease after adolescence.
- C. an acceptor of the recessive gene that causes the disease.
- D. susceptible to the disease in late adulthood.
Correct Answer: A
Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.
A client at 37 weeks gestation presents to labor and delivery with contractions every two minutes. The nurse observes several shallow small vesicles on her pubis, labia, and perineum. The nurse should recognize the client is exhibiting symptoms of which condition?
- A. Genital Warts
- B. Syphilis
- C. Herpes Simplex Virus
- D. German Measles
Correct Answer: C
Rationale: The correct answer is C: Herpes Simplex Virus (HSV). HSV can present with small vesicles on the genital area, and it is a concern during labor due to the risk of transmission to the newborn. Genital warts (Choice A) are caused by the human papillomavirus (HPV) and typically present as flesh-colored growths, not vesicles. Syphilis (Choice B) manifests as painless sores and can have systemic effects but does not typically present with vesicles. German measles (Choice D), also known as Rubella, is a viral illness characterized by a red rash, fever, and lymphadenopathy, not vesicles.
Before meiosis, a sperm cell:
- A. contains 46 chromosomes.
- B. contains two X chromosomes.
- C. is significantly larger than an egg cell.
- D. contains both an X and a Y chromosome.
Correct Answer: A
Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.
In the Ballard Gestational Age Assessment Tool, the nurse determines that a 15-month-old infant has a gestational age of 42 weeks. Based on this finding, which intervention is most important for the nurse to implement?
- A. Provide blow-by oxygen
- B. Provide a capillary blood glucose test
- C. Draw arterial blood gases
- D. Apply a pulse oximeter to the foot
Correct Answer: B
Rationale: Late preterm infants, such as those with a gestational age of 42 weeks, are at higher risk for hypoglycemia due to immature metabolic regulation. Monitoring capillary blood glucose is crucial to detect and manage hypoglycemia promptly. Providing blow-by oxygen (Choice A) is not indicated for an infant at risk for hypoglycemia. Drawing arterial blood gases (Choice C) is not the primary intervention for assessing hypoglycemia. Applying a pulse oximeter to the foot (Choice D) is not directly related to monitoring blood glucose levels in this context.