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There are 80 mg in 0.8 mL of Acetaminophen Concentrated Infant Drops. If the proper dosage for a four-year-old child is 240 mg, how many milliliters should the child receive?
- A. 0.8 mL
- B. 1.6 mL
- C. 2.4 mL
- D. 3.2 mL
Correct Answer: C
Rationale: To find out how many milliliters the child should receive, divide the total required dosage of 240 mg by the concentration of the medication, which is 80 mg per 0.8 mL. 240 mg · 80 mg/mL = 3 mL. Since each dose is 0.8 mL, the total dosage for the child would be 3 doses x 0.8 mL per dose = 2.4 mL. Therefore, the correct answer is 2.4 mL. Choice A (0.8 mL) is the concentration of the medication, not the total dose. Choices B (1.6 mL) and D (3.2 mL) are incorrect calculations that do not consider the concentration of the medication and the total required dosage correctly.
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A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $1.75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?
- A. $2,240
- B. $2,800
- C. $3,360
- D. $4,480
Correct Answer: C
Rationale: To find the perimeter of a hexagonal field with 6 sides, multiply the length of one side (320 feet) by the number of sides (6): 320 x 6 = 1920 feet. The total cost of the fencing material can be calculated by multiplying the perimeter by the cost per foot: 1920 feet x $1.75 = $3360. Therefore, the farmer will need to spend $3,360 on fencing material to enclose the perimeter of the field. Choice A, B, and D are incorrect as they do not accurately calculate the total cost based on the given measurements and cost per foot.
A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?
- A. 24
- B. 28
- C. 36
- D. 38
Correct Answer: C
Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.
Given the double bar graph shown below, which of the following statements is true?
- A. Group A is negatively skewed, while Group B is approximately normal.
- B. Group A is positively skewed, while Group B is approximately normal.
- C. Group A is approximately normal, while Group B is negatively skewed.
- D. Group A is approximately normal, while Group B is positively skewed.
Correct Answer: B
Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.
Solve for x: 4(2x - 6) = 10x - 6
- A. x = 5
- B. x = -7
- C. x = -9
- D. x = 10
Correct Answer: C
Rationale: To solve the equation 4(2x - 6) = 10x - 6, first distribute 4 into the parentheses: 8x - 24 = 10x - 6. Next, simplify the equation by rearranging terms: 8x - 10x = -6 + 24, which gives -2x = 18. Solving for x by dividing by -2 on both sides gives x = -9. Therefore, the correct answer is x = -9. Choice A (x = 5), Choice B (x = -7), and Choice D (x = 10) are incorrect solutions obtained by errors in solving the equation.
A patient was taking 310 mg of an antidepressant daily. The doctor reduced the dosage by 1/5, and then reduced it again by 20 mg. What is the patient's final dosage?
- A. 20 mg
- B. 42 mg
- C. 228 mg
- D. 248 mg
Correct Answer: C
Rationale: To calculate the final dosage, first find 1/5 of 310 mg, which is 62 mg, and subtract it from the original dosage. This gives 310 mg - 62 mg = 248 mg. Then, subtract an additional 20 mg from the result to get the final dosage: 248 mg - 20 mg = 228 mg. Therefore, the patient's final dosage is 228 mg. Choice A (20 mg) is incorrect because it only considers the second reduction of 20 mg and misses the initial reduction by 1/5. Choice B (42 mg) is incorrect as it miscalculates the reduction amounts. Choice D (248 mg) is incorrect as it does not account for the second reduction of 20 mg.