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What is the probability of flipping a coin and getting heads?
- A. 1/2
- B. 1/3
- C. 1/4
- D. 1/5
Correct Answer: A
Rationale: The correct answer is A: 1/2. When flipping a fair coin, there are two possible outcomes: heads or tails. The probability of getting heads is 1 out of 2 possible outcomes, which can be expressed as 1/2. Choice B, 1/3, is incorrect because a fair coin only has two sides. Choices C and D, 1/4 and 1/5, are also incorrect as they do not represent the correct probability of getting heads when flipping a coin.
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Solve for x: 2x + 4 = x - 6
- A. x = -12
- B. x = 10
- C. x = -16
- D. x = -10
Correct Answer: D
Rationale: To solve the equation 2x + 4 = x - 6, first, subtract x from both sides to get x + 4 = -6. Then, subtract 4 from both sides to isolate x, resulting in x = -10. Therefore, the correct answer is x = -10. Choice A is incorrect as it does not follow the correct steps of solving the equation. Choice B is incorrect as it is the result of combining x terms incorrectly. Choice C is incorrect as it is not the correct result of solving the equation step by step.
Over several years, a real estate agent sold houses, with one year having an outlier where she sold 11 houses. Which of the following measures will most accurately reflect the number of houses she sold per year?
- A. mean
- B. median
- C. mode
- D. range
Correct Answer: B
Rationale: The outlier of 11 would skew the data if the mean or range were used. The median, however, is not affected by outliers and is the most appropriate measure for reflecting the number of houses she sold per year. In this scenario, the data set does not have a mode as each value occurs only once, making mode not the most appropriate choice.
A patient was taking 310 mg of an antidepressant daily. The doctor reduced the dosage by 1/5, and then reduced it again by 20 mg. What is the patient's final dosage?
- A. 20 mg
- B. 42 mg
- C. 228 mg
- D. 248 mg
Correct Answer: C
Rationale: To calculate the final dosage, first find 1/5 of 310 mg, which is 62 mg, and subtract it from the original dosage. This gives 310 mg - 62 mg = 248 mg. Then, subtract an additional 20 mg from the result to get the final dosage: 248 mg - 20 mg = 228 mg. Therefore, the patient's final dosage is 228 mg. Choice A (20 mg) is incorrect because it only considers the second reduction of 20 mg and misses the initial reduction by 1/5. Choice B (42 mg) is incorrect as it miscalculates the reduction amounts. Choice D (248 mg) is incorrect as it does not account for the second reduction of 20 mg.
If Hannah spends at least $16 on 4 packages of coffee, which of the following inequalities represents the possible costs?
- A. 16 ≥ 4p
- B. 16 < 4p
- C. 16 > 4p
- D. 16 ≤ 4p
Correct Answer: D
Rationale: To represent the relationship between the number of packages of coffee and the minimum cost, the inequality can be written as 4p ≥ 16 (cost is at least $16). This inequality can also be expressed as 16 ≤ 4p, which reads as the cost being less than or equal to $16. Therefore, the correct answer is D. Choice A (16 ≥ 4p) implies that the cost can be greater than or equal to $16, which does not align with the statement that Hannah spends at least $16. Choice B (16 < 4p) suggests that the cost is less than $16, which contradicts the given information. Choice C (16 > 4p) indicates that the cost is greater than $16, which is not accurate based on the scenario provided.
Given the double bar graph shown below, which of the following statements is true?
- A. Group A is negatively skewed, while Group B is approximately normal.
- B. Group A is positively skewed, while Group B is approximately normal.
- C. Group A is approximately normal, while Group B is negatively skewed.
- D. Group A is approximately normal, while Group B is positively skewed.
Correct Answer: B
Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.