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Which type of bacteria can survive in extreme salty environments?
- A. Psychrophiles
- B. Halophiles
- C. Thermophiles
- D. Mesophiles
Correct Answer: B
Rationale: The correct answer is B: Halophiles. Halophiles are bacteria that can survive in extreme salty environments. They have adapted to thrive in high salt concentrations. Psychrophiles (A) thrive in cold temperatures, Thermophiles (C) thrive in high temperatures, and Mesophiles (D) thrive in moderate temperatures. Therefore, they are not adapted to survive in extreme salty environments like Halophiles.
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A child with diarrhea had stool microscopy revealing cysts with four nuclei. What is the most likely causative agent?
- A. Entamoeba histolytica
- B. Giardia lamblia
- C. Balantidium coli
- D. Trichomonas hominis
Correct Answer: A
Rationale: The correct answer is A: Entamoeba histolytica. This pathogen is known to cause amoebic dysentery, characterized by diarrhea with bloody or mucoid stools. The presence of cysts with four nuclei in the stool microscopy is a characteristic feature of Entamoeba histolytica. Other choices are incorrect because Giardia lamblia typically presents with binucleate cysts, Balantidium coli is a ciliated protozoan, and Trichomonas hominis is a non-pathogenic parasite found in the human intestine.
The generation time of bacteria refers to:
- A. The time for DNA replication
- B. The time for a cell to divide and double in number
- C. The time for spore formation
- D. The time for toxin production
Correct Answer: B
Rationale: The correct answer is B: The generation time of bacteria refers to the time for a cell to divide and double in number. This is because the generation time is the period required for one bacterial cell to undergo binary fission and divide into two identical daughter cells. This process involves DNA replication, followed by cell division, resulting in an increase in the number of bacterial cells.
Incorrect choices:
A: The time for DNA replication - While DNA replication is a crucial part of bacterial growth and reproduction, it does not solely define the generation time.
C: The time for spore formation - Spore formation is a specific process in certain bacteria and is not synonymous with the generation time.
D: The time for toxin production - Toxin production is an independent process in bacteria and does not directly relate to the generation time.
Ribosomes take part in:
- A. protein synthesis
- B. break down of different substances
- C. oxidative phosphorylation
- D. inactivation of antibiotics
Correct Answer: A
Rationale: Ribosomes are responsible for protein synthesis, where they translate the genetic information from mRNA into specific amino acid sequences to form proteins. This process occurs in both prokaryotic and eukaryotic cells. Ribosomes do not participate in the breakdown of substances, which is mainly carried out by lysosomes or proteasomes. Oxidative phosphorylation involves the generation of ATP in mitochondria, not ribosomes. Ribosomes do not inactivate antibiotics; this is typically done by enzymes or chemical modifications. Therefore, the correct answer is A as ribosomes play a crucial role in protein synthesis.
Which of the following viral infections can result in chronic carrier state.
- A. HBV
- B. HCV
- C. HDV
- D. All of these
Correct Answer: D
Rationale: The correct answer is D: All of these. HBV, HCV, and HDV can all lead to chronic carrier states due to their ability to establish persistent infections in the liver. HBV can result in chronic hepatitis, cirrhosis, and even liver cancer. HCV can also lead to chronic hepatitis and liver damage. HDV is a defective virus that requires HBV for replication and can worsen the outcome of HBV infection, potentially leading to chronic liver disease. Therefore, all three viruses have the potential to cause chronic carrier states.
A patient suffering form tuberculosis was treated with rifampicin, which caused drug resistance of tuberculosis mycobacteria. In order to reduce mycobacteria resistance, rifampicin should be combined with the following drug:
- A. Isoniazid
- B. Acyclovir
- C. Intraconazole
- D. Metronidazole
Correct Answer: A
Rationale: The correct answer is A: Isoniazid. When rifampicin is used alone, there is a risk of developing resistance. Isoniazid is commonly used in combination with rifampicin to prevent resistance by targeting different mechanisms in the bacteria. Isoniazid works by inhibiting mycolic acid synthesis, while rifampicin targets RNA polymerase. This combination therapy is known as the first-line treatment for tuberculosis. Choices B, C, and D are incorrect because they do not have the same mechanism of action as isoniazid and would not be effective in preventing rifampicin resistance.