Nokea
A client in labor requests nonpharmacological pain management. Which of the following nursing actions promotes client comfort?
- A. Assisting the client into a squatting position
- B. Having the client lie in a supine position
- C. Applying fundal pressure during contractions
- D. Encouraging the client to void every 6 hours
Correct Answer: A
Rationale: Assisting the client into a squatting position promotes comfort during labor. This position can help relieve pain by utilizing gravity, allowing the pelvic outlet to widen, and potentially facilitating the progress of labor. Lying in a supine position (Choice B) can hinder labor progression and increase discomfort. Applying fundal pressure (Choice C) can be inappropriate and may cause harm as it is not routinely recommended during labor. Encouraging the client to void every 6 hours (Choice D) is important for bladder management but does not directly address pain relief during labor.
You may also like to solve these questions
Is color blindness a sex-linked abnormality?
- A. TRUE
- B. FALSE
- C. Sometimes
- D. Always
Correct Answer: A
Rationale: The correct answer is A: TRUE. Color blindness is indeed a sex-linked abnormality as it is often associated with genes on the X chromosome. Since males have only one X chromosome, they are more likely to inherit color blindness if the gene is present. This makes color blindness more common in males. Choice B (FALSE) is incorrect because color blindness is linked to the X chromosome. Choices C (Sometimes) and D (Always) are incorrect as color blindness is consistently tied to the X chromosome.
A primigravida at 36 weeks gestation who is RH-negative experienced abdominal trauma in a motor vehicle collision. Which assessment finding is most important for the nurse to report to the healthcare provider?
- A. Fetal heart rate at 162 beats per minute
- B. Mild contractions every 10 minutes
- C. Trace of protein in the urine
- D. Positive fetal hemoglobin testing
Correct Answer: D
Rationale: The correct answer is 'Positive fetal hemoglobin testing' (D). Positive fetal hemoglobin testing (Kleihauer-Betke test) indicates fetal-maternal hemorrhage, which is critical in an RH-negative mother due to the risk of isoimmunization. This condition can lead to sensitization of the mother's immune system against fetal blood cells, potentially causing hemolytic disease of the newborn in subsequent pregnancies. Reporting this finding promptly is crucial for appropriate management and interventions. Choices A, B, and C are not as critical in this scenario. While monitoring fetal heart rate and contractions is important, the detection of fetal-maternal hemorrhage takes precedence due to the serious implications it poses for the current and future pregnancies of an RH-negative mother.
What causes sickle-cell anemia?
- A. A chromosomal abnormality.
- B. A single segment found only on the Y chromosome.
- C. A recessive gene.
- D. A decrease in estrogen levels.
Correct Answer: C
Rationale: Sickle-cell anemia is a genetic disorder caused by inheriting two copies of a recessive gene, one from each parent. The correct answer is C. Choice A is incorrect because sickle-cell anemia is not primarily caused by a chromosomal abnormality. Choice B is incorrect as the condition is not linked to a single segment found only on the Y chromosome. Choice D is unrelated as it mentions a decrease in estrogen levels, which is not a cause of sickle-cell anemia.
According to a study in the year 2013 by Fellman, if a woman is a twin, if her mother was a twin, or if she has previously borne twins, then:
- A. she will bear only monozygotic (MZ) twins.
- B. the chances of her becoming pregnant decrease.
- C. she is likely to be a healthy mother.
- D. the chances rise that she will bear twins.
Correct Answer: D
Rationale: According to the study, the chances of a woman bearing twins increase if she is a twin herself, if her mother was a twin, or if she has previously borne twins. Therefore, the correct answer is D. Choice A is incorrect because the study does not specify that she will bear only monozygotic twins. Choice B is incorrect as the study does not mention any decrease in the chances of becoming pregnant. Choice C is incorrect because the study does not provide information about the woman's health status, focusing instead on the likelihood of bearing twins.
If an individual receives a recessive gene for eye color from both parents, the:
- A. gender of the child will not determine the expression of that trait.
- B. recessive trait will be expressed in the child.
- C. recessive trait will be expressed in all the offspring.
- D. recessive trait will be suppressed, and the dominant trait will not be expressed.
Correct Answer: B
Rationale: When an individual inherits a recessive gene for eye color from both parents, the recessive trait will be expressed in the child. This is because having two copies of the recessive gene overrides the presence of any dominant gene. Choice A is incorrect because the expression of the trait is determined by the genetic makeup, not the gender of the child. Choice C is incorrect as the expression of the recessive trait is certain when both parents pass on the recessive gene, but it does not mean that all offspring will express the trait. Choice D is incorrect because if both parents provide a recessive gene, the dominant trait will not be expressed in the child, but it does not mean it will be suppressed; rather, the recessive trait will be expressed.