Nokea
What is the role of hydrochloric acid in the stomach?
- A. Break down carbohydrates
- B. Break down proteins
- C. Emulsify fats
- D. None of the above
Correct Answer: B
Rationale: The correct answer is B: Break down proteins. Hydrochloric acid in the stomach helps to activate pepsin, an enzyme that breaks down proteins into smaller peptides. This process is essential for proper digestion of proteins. Choice A is incorrect because carbohydrates are broken down by amylase enzymes in the mouth and small intestine. Choice C is incorrect because emulsification of fats occurs in the small intestine with the help of bile. Choice D is incorrect as hydrochloric acid plays a significant role in the digestion of proteins in the stomach.
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In which of the following segments of the gastrointestinal tract is primary carcinoma least common?
- A. esophagus
- B. stomach
- C. small intestine
- D. colon
Correct Answer: C
Rationale: The correct answer is C: small intestine. Primary carcinoma is least common in the small intestine due to its relatively lower exposure to carcinogens and slower cellular turnover compared to other segments like the colon. The esophagus is prone to carcinoma due to chronic irritation from acid reflux. The stomach is susceptible due to factors like Helicobacter pylori infection and dietary habits. The colon is at higher risk due to frequent exposure to fecal carcinogens. In summary, the small intestine has the least incidence of primary carcinoma due to lower exposure to risk factors.
At which relative exercise intensity would you expect to utilize the most intramuscular triglycerides?
- A. 25% VO2 max (i.e. 25% of aerobic capacity)
- B. 65% VO2 max
- C. 85% VO2 max
- D. 150% VO2 max
Correct Answer: B
Rationale: The correct answer is B (65% VO2 max) because at this intensity, the body primarily uses a combination of fats and carbohydrates for energy production. Intramuscular triglycerides are a source of fat utilized during moderate-intensity exercise. At 25% VO2 max (choice A), the body predominantly uses carbohydrates, while at 85% VO2 max (choice C) and 150% VO2 max (choice D), the reliance shifts towards carbohydrates due to the higher intensity levels. Therefore, option B is the most suitable intensity for utilizing intramuscular triglycerides efficiently.
The nurse caring for an 80-year-old woman who is undergoing extensive bowel preparation for a colonoscopy. The nurse should most closely monitor the patient for which potential complication?
- A. Diarrhea
- B. Metabolic acidosis
- C. Fatigue
- D. Dyspnea
Correct Answer: B
Rationale: The correct answer is B: Metabolic acidosis. During bowel preparation for a colonoscopy, the patient may experience fluid and electrolyte imbalances, leading to metabolic acidosis. The nurse should closely monitor for signs such as confusion, weakness, and increased respiratory rate. Diarrhea (choice A) is expected during bowel preparation but does not directly lead to metabolic acidosis. Fatigue (choice C) and dyspnea (choice D) are less likely complications of bowel preparation and do not directly relate to metabolic acidosis.
The three pairs of extrinsic salivary glands are:
- A. parotid sublingual and ethmoidal
- B. Parotid buccal and submaxillary
- C. Parotid sub mandibular and buccal
- D. Parotid Submandibular and sublingual
Correct Answer: D
Rationale: The correct answer is D because the extrinsic salivary glands are the parotid, submandibular, and sublingual glands. The parotid gland is located near the ear, the submandibular gland is under the mandible, and the sublingual gland is under the tongue.
A is incorrect because the ethmoidal gland is not an extrinsic salivary gland. B is incorrect because the buccal gland is not an extrinsic salivary gland. C is incorrect because the buccal gland is not an extrinsic salivary gland; it is a minor salivary gland located in the cheek.
One of the major functions of bile salts is to
- A. break down fat to fatty acids and glycerol.
- B. emulsify fat to fatty droplets.
- C. break down fat to cholesterol and lecithin.
- D. emulsify fats to bilirubin.
Correct Answer: B
Rationale: The correct answer is B because bile salts emulsify fat into smaller droplets, increasing the surface area for enzymes to break down fats into fatty acids and glycerol. This aids in fat digestion and absorption in the small intestine. Choice A is incorrect as bile salts do not directly break down fats into fatty acids and glycerol. Choice C is incorrect as bile salts do not break down fats into cholesterol and lecithin. Choice D is incorrect as bile salts do not emulsify fats to bilirubin, but rather help in the digestion of fats.